Dimensionally Correct Nyob rau hauv ib qho kev qhia algebraic, tag nrho cov ntsiab lus uas ntxiv lossis rho tawm yuav tsum muaj tib qhov ntev. Qhov no txhais tau hais tias txhua lub sij hawm nyob rau sab laug-sab ntawm ib qho kev sib npaug yuav tsum muaj qhov sib npaug li txhua lub sij hawm ntawm sab xis.
Dab tsi yog qhov loj me yog qhov tseeb?
t=S+av.
Puas yog F 2π √ K M qhov tseeb?
txhawm rau txheeb xyuas qhov tseeb qhov tseeb, peb yuav tsum cais LHS thiab RHS ntawm qhov sib npaug muab raws li qhov tseem ceeb ntawm lub cev. LHS: RHS: Yog li, RHS=LHS, li no sib npaug yog qhov tseeb.
Yog T 2π √ l g dimensionally correct?
Muab, Lub Sijhawm lub sijhawm ntawm lub pendulum yooj yim, T=2π√lg → (1) qhov twg l yog qhov ntev ntawm lub pendulum thiab g yog acceleration vim lub ntiajteb txawj nqus. Thaum peb yuav siv qhov ntsuas qhov sib npaug ntawm qhov sib npaug (1), 2π yog qhov tsis tu ncua uas tau txais ntau ntxiv yog li nws yuav tsis saib xyuas. … Qhov no txhais tau hais tias qhov sib npaug muab yog dimensionally raug.
Puas yog T 2π √ m G dimensionally correct?
T-- lub sijhawm ntawm lub pendulum yooj yim. m --- qhov loj ntawm bob. g---- acceleration vim lub ntiajteb txawj nqus.
