Tus lej DBE tuaj yeem suav los ntawm cov qauv siv cov lej hauv qab no: DBE=UN=PBoR=C - (H/2) + (N/2) +1, qhov twg: C=tus naj npawb ntawm carbon atoms, H=tus naj npawb ntawm hydrogen thiab halogen atoms, thiab N=tus naj npawb ntawm nitrogen atoms. Ib DBE=ib lub nplhaib lossis ob daim ntawv cog lus.
Yuav ua li cas koj thiaj nrhiav tau ob daim ntawv sib npaug?
- ob daim ntawv sib npaug.
- 1) Xam tus lej siab tshaj 2n + 2 ntawm H atoms.
- 2) Tshem tawm tus lej tiag ntawm H atoms.
- 3) Faib 2.
- 2) rho tawm tus lej ntawm H atoms: 16 - 12=4.
- 3) thiab muab faib ua ob: 4 / 2=2.
- 1) Xam tus lej siab tshaj plaws ntawm H atoms (2n + 2)
- 2) Tshem tawm tus lej tiag ntawm H atoms.
DBE ntawm 4 txhais li cas?
DBE tus nqi ntawm 4= plaub lub ncuav qab zib, plaub lub nplhaib, peb lub ncuav qab zib + ib lub nplhaib (ib qho piv txwv classic yog benzene), ob lub ncuav qab zib + ob lub nplhaib, ib lub ncuav qab zib daim ntawv cog lus + peb lub nplhaib, ob daim ntawv cog lus triple, ib daim ntawv cog lus triple + ob daim ntawv cog lus ob, ib daim ntawv cog lus triple + ob lub nplhaib.
Yuav ua li cas yog tus qauv rau qib ntawm unsaturation?
Qhov txawv ntawm qhov xav tau ntawm cov hydrogens thiab cov naj npawb ntawm cov hydrogen atoms pom=8 - 4. Yog li, cov molecule xav tau 4 ntau hydrogen atoms kom saturated. Los ntawm cov degree ntawm unsaturation formula rau cov compound no, tus nqi tau raws li degree ntawm unsaturation yog: DU=4/2=2.
DBE ntawm benzene yog dab tsi?
A molecule muaj obdaim ntawv cog lus los yog lub nplhaib yog suav tias yog ib qho Unsaturated molecule. BENZENE: Lub nplhaib uas muaj rau cov pa roj carbon atom uas tau sib koom ua ke los ntawm ib qho thiab ob daim ntawv cog lus sib txawv. Cov mis mos molecular ntawm nws yog C6H6. Lub DBE ntawm tag nrho cov qauv yog 4 uas yog sib npaug rau benzene.
