Puas yog qhov kev xeem thib ob?

Cov txheej txheem:

Puas yog qhov kev xeem thib ob?
Puas yog qhov kev xeem thib ob?
Anonim

Qhov thib ob derivative yuav yog siv los txiav txim siab hauv zos extrema ntawm kev ua haujlwm raws li qee yam xwm txheej. Yog tias qhov kev ua haujlwm muaj qhov tseem ceeb rau qhov twg f′(x)=0 thiab qhov thib ob derivative yog qhov zoo ntawm qhov no, ces f muaj qhov tsawg kawg nkaus hauv zos ntawm no. … Qhov txheej txheem no hu ua Second Derivative Test for Local Extrema.

Puas yog qhov kev xeem thib ob puas muaj tseeb?

Kev tsis lees paub thiab lees paub

Kev ntsuas thib ob tsis tuaj yeem lees paub tsim qhov no. Nws tsuas muaj peev xwm ua kom tiav cov txiaj ntsig tau lees paub txog lub zos extrema.

Thaum twg peb tsis tuaj yeem siv qhov kev xeem thib ob?

Yog f′(c)=0 thiab f″(c)=0, lossis yog f″(c) tsis muaj, ces qhov kev xeem tsis tiav.

Vim li cas qhov kev xeem thib ob ua tsis tiav?

Yog f (x0)=0, qhov kev xeem ua tsis tiav thiab ib qho yuav tsum tau tshawb xyuas ntxiv, los ntawm kev noj cov khoom siv ntxiv, lossis tau txais cov ntaub ntawv ntxiv txog daim duab. Dhau li ntawm qhov siab tshaj plaws lossis qhov tsawg kawg nkaus, qhov taw tes no kuj tseem tuaj yeem yog kab rov tav taw tes ntawm inflection.

Koj ua pov thawj li cas qhov kev xeem thib ob?

Second Derivative Test

  1. Yog f′(c)<0 f″ (c) < 0 ces x=c yog tus txheeb ze tshaj plaws.
  2. Yog f′(c)>0 f″ (c) > 0 ces x=c yog tus txheeb ze yam tsawg kawg nkaus.
  3. Yog f′(c)=0 f″ (c)=0 ces x=c tuaj yeem yog tus txheeb ze tshaj plaws, txheeb ze yam tsawg lossis tsis yog.

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